Tuesday, August 18, 2015

BATE Borisov vs Partizan

In the first meeting of playoffs to qualify in the group stage of the Champions League against each other, we will see the teams of the Belarusian Bate Borisov and the Serbian Partizan Belgrade. Take a look at our football prediction, regarding the upcoming event.
The hosts are on the verge of their fifth participation in the groups of the most prestigious European club tournament for the past few years. The Serbs also will try to qualify among the most powerful clubs in Europe after several failed attempts in recent seasons in the race.
Bate Borisov overcame two rivals on its way to this match from free-soccer-picks in the previous two rounds of qualifying. The Irish eliminated successively the champion Dundalk, after a 2:1 victory and a draw in Ireland of 0:0. In the next stage, the Belarusians overcame the Hungarian champion Videoton, after 1:1 in Hungary and a win of 1:0 at home in the second leg. In the local Championship, Bate Borisov is the leader with three points more than second Dynamo Minsk. Having played in 16 rounds, they have made 12 wins, three draws and one defeat. In the last two rounds, however, the team failed to score a hit and forfeited loss with 0:1 by Dynamo Minsk and Gomel with 0:0. For the upcoming duel, the Belarusian champion will be able to use and Alexander Hleb.
Partizan Belgrade also overcame two rivals to reach out to this meeting. In the first round of qualifying, the Serbs suspended the Georgian champion Dila Gori, after 2 wins with 1:0 and 2:0. Partizan Belgrade in the next stage was up against Romanian champion Steaua and managed to overcome it after a 1:1 draw in Romania and the victory with 4:2 in Belgrade. In the local championship, the team is performing far more poorly, 3 wins and 2 defeats. Over the weekend, the Serbian champion lost with 3:2 against Vojvodina. Ivan Bandalovski and Valeri Bozhinov in are included in the group for this match from free-soccer-picks and are expected to lead the attack.
Our football forecast is 1.

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